Colorado cities named among ‘best' real estate markets in the country

Posted at 11:05 AM, Aug 28, 2017

DENVER – Denver and several other Colorado cities made a list of the “best” real estate markets in the country.

Denver is the 10th “best” city for real estate and the third-best when comparing only cities with more than 300,000 residents, according to financial services website WalletHub. Denver is followed closely by suburbs Thornton, Aurora and Arvada.

What makes a real estate market the “best”? WalletHub lumped together a variety of different factors, so its list doesn’t reflect which cities are, say, the most affordable or the least competitive for buyers, specifically.

The site’s analysts did look at factors like affordability, but they also included mortgage delinquency rates, average amount of time on the market, home price appreciation and vacancy rates, among others. They then averaged those factors together to give each city an overall score.

Based on all of those factors combined, the Dallas, Texas suburb of Frisco takes the top spot on the list, followed by nearby McKinney and Allen. Seattle was ranked first among large cities.

Here are the 15 overall “best” markets in the country, according to WalletHub:

1. Frisco, TX
2. McKinney, TX
3. Allen, TX
4. Cary, NC
5. Richardson, TX
6. Seattle, WA
7. Bellevue, WA
8. Carrollton, TX
9. Nashville, TN
10. Denver, CO
11. Thornton, CO
12. Aurora, CO
13. Arvada, CO
14. Murfreesboro, TN
15. Gilbert, AZ

Other Colorado cities that made the top 50 include Fort Collins (17), Colorado Springs (19), Centennial (20), Longmont (21), Greeley (26), Westminster (28), Lakewood (40) and Pueblo (46).

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